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How Big Is Each Manager's Team?

easySQLGroupByNull Handling

Kestrel Labs is sizing a training programme for people who manage others, and needs to know how many managers there are and how many direct reports each of them carries.

The reporting line lives on the employee row: each person's row holds the id of the person they report to. Managers are therefore not marked anywhere — somebody is a manager exactly when other rows point at them. The people at the top of a line have nothing to point at, so their own slot holds NULL, and those employees are not part of this count in either direction: they are not reports, and being at the top does not by itself make somebody a manager.

employees — one row per employee. manager_id holds the id of that person's manager, or NULL for someone who reports to nobody.

id name department_id salary hire_date manager_id
1 Ava Chen 1 145000 2021-03-14 NULL
2 Ben Ortiz 1 118000 2022-06-01 1
3 Cara Novak 1 121000 2023-01-10 1
4 Deshawn Lee 2 95000 2020-09-23 NULL
5 Elin Kask 2 88000 2022-11-05 4
6 Farid Amiri 3 76000 2023-04-18 NULL
7 Grace Kim 4 132000 2021-07-30 NULL
8 Hugo Silva 4 110000 2023-02-14 7
9 Ines Duarte 4 104000 2023-08-01 7
10 Jonas Weber 2 91000 2021-12-19 4

The table already exists in the database — there is nothing to create or load.

Task: Write a query returning two columns, manager_id and num_reports, with one row for each employee id that appears as somebody's manager, and how many people report to them. Employees with no manager recorded must not form a row of their own. Rows come back sorted by manager_id, smallest first.

Example output — shape only, on an invented company; both the ids and the counts are made up.

manager_id num_reports
3 5
6 3
9 8

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